Date: Thu, 24 Jun 2010 10:09:25 -0700 From: Carl Johnson <carlj@peak.org> To: freebsd-questions@freebsd.org Subject: Re: .sh check for numeric content Message-ID: <87hbksmk6y.fsf@cjlinux.localnet> In-Reply-To: <87lja4mlme.fsf@cjlinux.localnet> (Carl Johnson's message of "Thu\, 24 Jun 2010 09\:38\:33 -0700") References: <4C22B3D7.6070102@comclark.com> <20100624033257.2D074BEA6@kev.msw.wpafb.af.mil> <87lja4mlme.fsf@cjlinux.localnet>
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Carl Johnson <carlj@peak.org> writes:
> vogelke+unix@pobox.com (Karl Vogel) writes:
>
>>>> On Thu, 24 Jun 2010 09:24:39 +0800,
>>>> Aiza <aiza21@comclark.com> said:
>>
>> A> Receiving a variable from the command line that is suppose to contain
>> A> numeric values. How do I code a test to verify the content is numeric?
>>
>> The script below will work with the Bourne or Korn shell.
>> Results for "0 1 12 1234 .12 1.234 12.3 1a a1":
>>
>> 0 is numeric
>> 1 is numeric
>> 12 is numeric
>> 1234 is numeric
>> .12 is numeric
>> 1.234 is numeric
>> 12.3 is numeric
>> 1a is NOT numeric
>> a1 is NOT numeric
>
> You might want to try testing "123..45".
> I tried changing:
>> if expr "$arg" : "[0-9]*[\.0-9]*$" > /dev/null
> to:
> if expr "$arg" : "[0-9]*\.*[0-9]*$" > /dev/null
> but it still claims that it is numeric, so *I* must be missing
> something.
I just realized that I had a stupid mistake there and should have
used:
if expr "$arg" : "[0-9]*\.[0-9]*$" > /dev/null
--
Carl Johnson carlj@peak.org
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