Date: Tue, 5 Mar 2024 13:11:13 +0500 From: "Eugene M. Zheganin" <eugene@zhegan.in> To: freebsd-pf@freebsd.org Subject: dumb question about "no state" Message-ID: <d38d0e14-4b8b-420f-b9e7-62c521f003aa@zhegan.in>
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Hello, I hope the following is self-explanatory: pfctl -vs rules: [...] pass quick proto tcp all flags A/A no state [ Evaluations: 1125881 Packets: 972814 Bytes: 421350757 States: 82 ] [ Inserted: uid 0 pid 28187 State Creations: 82 ] man pf.conf: pass The packet is passed; state is created unless the no state option is specified. Why does this rule create states ? Am I misreading/misunderstanding the part "state is created unless the no state option is specified" ? Thanks. Eugene.
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