Date: 14 Feb 2003 17:36:01 -0800 From: Arun Sharma <arun.sharma@intel.com> To: Marcel Moolenaar <marcel@xcllnt.net> Cc: freebsd-ia64@FreeBSD.ORG Subject: Re: Maxmem should be bytes ? Message-ID: <ud6lu1g1q.fsf@unix-os.sc.intel.com> In-Reply-To: <20030214010244.GA1344@athlon.pn.xcllnt.net> References: <200302080111.h181Bkr26574@unix-os.sc.intel.com> <u1y2b3eb7.fsf@unix-os.sc.intel.com> <20030214002346.GA1267@athlon.pn.xcllnt.net> <uvfzn1yev.fsf@unix-os.sc.intel.com> <20030214010244.GA1344@athlon.pn.xcllnt.net>
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Marcel Moolenaar <marcel@xcllnt.net> writes:
> > New code that tries to use ia64_ptob(Maxmem) for something other than
> > VHPT sizing would be broken.
>
> Like machdep.c:164?
>
> printf("real memory = %ld (%ld MB)\n", ia64_ptob(Maxmem),
> ia64_ptob(Maxmem) / 1048576);
This one is ok, because it's before line 598. Any code executed after
line 598 would be broken.
>
> As for the fact that Maxmem is in bytes and physmem isn't: we define
> Maxmem to be equal to physmem (machdep.c:598). So they are in fact
> equal.
All I'm saying is:
--- machdep.c.old Fri Feb 14 17:32:26 2003
+++ machdep.c Fri Feb 14 17:33:22 2003
@@ -595,7 +595,7 @@
}
phys_avail[phys_avail_cnt] = 0;
- Maxmem = physmem;
+ Maxmem = ia64_ptob(physmem);
init_param2(physmem);
/*
i386 does something equivalent.
-Arun
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