Date: Sun, 18 Aug 2019 09:55:33 +0000 From: bugzilla-noreply@freebsd.org To: apache@FreeBSD.org Subject: maintainer-feedback requested: [Bug 239936] www/mod_auth_mysql_another: fix if linked with mariadb Message-ID: <bug-239936-16115-cPV9spPH2w@https.bugs.freebsd.org/bugzilla/> In-Reply-To: <bug-239936-16115@https.bugs.freebsd.org/bugzilla/> References: <bug-239936-16115@https.bugs.freebsd.org/bugzilla/>
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Bugzilla Automation <bugzilla@FreeBSD.org> has asked freebsd-apache mailing list <apache@FreeBSD.org> for maintainer-feedback: Bug 239936: www/mod_auth_mysql_another: fix if linked with mariadb https://bugs.freebsd.org/bugzilla/show_bug.cgi?id=3D239936 --- Description --- if the system uses mariadb, this error comes up: httpd: Syntax error on line 88 of /usr/local/etc/apache24/httpd.conf:=09=20= =20=20=20=20=20=20 Cannot load /usr/local/libexec/apache24/mod_auth_mysql.so into server:=09= =20=20=20=20=20=20=20 /usr/local/libexec/apache24/mod_auth_mysql.so: Undefined symbol=20=09=20=20= =20=20=20=20=20 "make_scrambled_password" The patch fixes this, run-tested, but I have not find a clean way to detect if the database in use is maria or mysql. Any ideas ? I tested with the #ifndef MYSQL_PORT, but this did not work.
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