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Date:      Wed, 13 Jun 2012 12:18:14 +0200
From:      Olivier Smedts <olivier@gid0.org>
To:        Irjohn Junus <i.junus@gmail.com>
Cc:        freebsd-fs@freebsd.org
Subject:   Re: gpart add -a 4096 vs 4k
Message-ID:  <CABzXLYNZPO90fA41HGcJ-D-thE7KT586S5k7eo41GxLXBrWuCQ@mail.gmail.com>
In-Reply-To: <CALXkR%2B879QJPNisOKA71yej9m1%2BUiz4cNopkoM42irmRoaBL-g@mail.gmail.com>
References:  <CALXkR%2B879QJPNisOKA71yej9m1%2BUiz4cNopkoM42irmRoaBL-g@mail.gmail.com>

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Hello,

2012/6/13 Irjohn Junus <i.junus@gmail.com>:
> Hello,
>
> Relatively new to FreeBSD and learning, I'm trying to partition my HDD an=
d
> align it to 4k sector.
>
> I do apologize if this has been answered before, I have Googled and read
> gpart(8) man page to no joy. Can anyone please advice why gpart add '-a
> 4096' doesn't yield the same result with '-a 4k'? Many thanks and capture=
s
> are below.
>
> Regards,
> Ronjns
>
>
>
> #gpart add -t freebsd-zfs -l hdd0 *-a 4096* da0
> da0p1 added
> # gpart show da0
> =3D> =A0 =A0 =A0 =A034 =A03907029101 =A0da0 =A0GPT =A0(1.8T)
> =A0 =A0 =A0 =A0 =A034 =A0 =A0 =A0 =A04062 =A0 =A0 =A0 - free - =A0(2M)
> =A0 =A0 =A0 =A0*4096 =A03907022848* =A0 =A01 =A0freebsd-zfs =A0(1.8T)
> =A03907026944 =A0 =A0 =A0 =A02191 =A0 =A0 =A0 - free - =A0(1.1M)
>
>
>
> # gpart add -t freebsd-zfs -l hdd0 *-a 4k* da0
> da0p1 added
> # gpart show da0
> =3D> =A0 =A0 =A0 =A034 =A03907029101 =A0da0 =A0GPT =A0(1.8T)
> =A0 =A0 =A0 =A0 =A034 =A0 =A0 =A0 =A0 =A0 6 =A0 =A0 =A0 - free - =A0(3.0k=
)
> =A0 =A0 =A0 =A0 =A0*40 =A03907029088* =A0 =A01 =A0freebsd-zfs =A0(1.8T)
> =A03907029128 =A0 =A0 =A0 =A0 =A0 7 =A0 =A0 =A0 - free - =A0(3.5k)

We're talking of sectors here, se "4096" does not mean 4 KB but 4096*512=3D=
2MB.

I think you should use "-a 8", because 4k sectors =3D 8*512B sectors.

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