Date: Thu, 31 Oct 2002 20:28:33 +1100 (EST) From: Bruce Evans <bde@zeta.org.au> To: "M. Warner Losh" <imp@bsdimp.com> Cc: tlambert2@mindspring.com, <rittle@labs.mot.com>, <rittle@latour.rsch.comm.mot.com>, <current@FreeBSD.ORG>, <dschultz@uclink.Berkeley.EDU> Subject: Re: Lack of real long double support Message-ID: <20021031202343.W8632-100000@gamplex.bde.org> In-Reply-To: <20021030.170154.35505346.imp@bsdimp.com>
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On Wed, 30 Oct 2002, M. Warner Losh wrote:
> The one issue that I've seen is
>
> long double a = 1.0L;
> long double b = 1.0L + LDBL_EPSION
> if (a == b) abort();
>
> which is what I'm trying to fix. (note, "1.0L" must be spelled
> "oneld()" and long double oneld() { return (1.0L);}) to avoid the
> optimizer getting it right.
Example of how fixing this breaks a similar assertion for DBL_ESPILON:
%%%
$ cat z.c
#include <float.h>
#include <floatingpoint.h>
long double oneld = 1.0L;
double oned = 1.0;
int
main()
{
test(2);
test(3);
}
int
test(int prec)
{
long double la, lb;
double a, b;
fpsetprec(prec);
la = oneld;
lb = oneld + LDBL_EPSILON;
if (la == lb)
printf("LDBL_EPSILON failed test 1 with prec %d\n", prec);
la = oneld;
lb = oneld + LDBL_EPSILON / 2;
if (la != lb)
printf("LDBL_EPSILON failed test 2 with prec %d\n", prec);
a = oned;
b = oned + DBL_EPSILON;
if (a == b)
printf("DBL_EPSILON failed test 1 with prec %d\n", prec);
a = oned;
b = oned + DBL_EPSILON / 2;
if (a != b)
printf("DBL_EPSILON failed test 2 with prec %d\n", prec);
}
$ cc -o z z.c
$ ./z
LDBL_EPSILON failed test 1 with prec 2
$ cc -O -o z z.c.
$ ./z
LDBL_EPSILON failed test 1 with prec 2
DBL_EPSILON failed test 2 with prec 3
%%%
The full brokenness only shows up with -O.
Bruce
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