Date: Wed, 14 Nov 2007 10:19:16 -0500 From: Bill Moran <wmoran@potentialtech.com> To: Martin McCormick <martin@dc.cis.okstate.edu> Cc: freebsd-questions@freebsd.org Subject: Re: /bin/sh Can one Easily Strip Path Name from $0? Message-ID: <20071114101916.c661f4ac.wmoran@potentialtech.com> In-Reply-To: <200711141508.lAEF8veZ083725@m.it.okstate.edu> References: <200711141508.lAEF8veZ083725@m.it.okstate.edu>
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In response to Martin McCormick <martin@dc.cis.okstate.edu>:
> I am ashamed to admit that I have been writing shell
> scripts for about 15 years but this problem has me stumped. $0
> is the shell variable which contains the script name or at least
> what name is linked to the script. The string in $0 may or may
> not contain a path, depending upon how the script was called. It
> is easy to strip off the path if it is always there
>
> #! /bin/sh
> PROGNAME=`echo $0 |awk 'BEGIN{FS="/"}{print $NF}'`
> echo $PROGNAME
>
> That beautifully isolates the script name but if you happen to
> call the script without prepending a path name such as when the
> script is in the execution path, you get an error because there
> are no slashes in the string so awk gets confused.
>
> Is there a better way to always end up with only the script name and
> nothing else no matter whether the path was prepended or not?
basename $0
--
Bill Moran
http://www.potentialtech.com
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