Date: Thu, 9 Apr 2009 15:32:51 +0200 (CEST) From: Oliver Fromme <olli@lurza.secnetix.de> To: freebsd-questions@FreeBSD.ORG, lconrad@Go2France.com Subject: awk question Message-ID: <200904091332.n39DWpDs037047@lurza.secnetix.de> In-Reply-To: <200904082253.AA2466447562@mail.Go2France.com>
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Len Conrad <lconrad@go2france.com> wrote:
>
> We need to print a line when the 3rd field (with trailing ";"
> delimiter) is, eg, exactly 5 lower case characters
>
> awk ' $3 ~ /^[a-z]{5,5};$/ {print $0} ' file
>
> ... doesn't work.
If ";" is the delimiter character, you need to tell awk
about it (i.e. use the -F option). This one should work:
awk -F';' '$3 ~ /^[a-z]{5}$/ {print}' file
If that still doesn't work for you, please specify your
file format more exactly, and provide an example of the
input lines.
Best regards
Oliver
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