Date: Tue, 8 Feb 2005 06:15:50 +0200 From: Giorgos Keramidas <keramida@hellug.gr> To: freebsd-questions@freebsd.org Subject: Re: Another grep question Message-ID: <20050208041550.GC23720@igloo.linux.gr> In-Reply-To: <1913197329.20050208034914@wanadoo.fr> References: <1667502496.20050208025619@wanadoo.fr> <200502071802.19719.reso3w83@verizon.net> <1913197329.20050208034914@wanadoo.fr>
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On 2005-02-08 03:49, Anthony Atkielski <atkielski.anthony@wanadoo.fr> wrote: > I'm looking for the hex character 93, which is an opening double > quotation mark in the Windows character set, not the literal string > "\0x93". Unless I'm mistaken, \0x93 in a regular expression means > "the character whose hex value is 93." Not really. Unless you have a shell that understands this sort of thing and expands the command line arguments to arbitrary 8-bit characters. Otherwise, "\0x93" means: A literal (escaped with '\') '0' character, followed by 'x', then followed by '9' and '3'.
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