Date: Sun, 20 Apr 2003 00:00:17 +0300 From: Enache Adrian <enache@rdslink.ro> To: current@freebsd.org Cc: das@freebsd.org Subject: recent bug in printf ? Message-ID: <20030419210017.GA1263@ratsnest.hole>
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$ gcc -x c - && ./a.out #include <stdio.h> int main() { printf("%.*g\n",8,0.00009); } ^D 9.0000000e-05 It appears that all others printf implementations will print '9e-05' there. It's at least what perl expects ( for its Gconvert() macro - and badly fails a lot of tests because of this ). The sprintf(3) man page claims: gG The double argument is converted in style f or e (or F or E for G conversions). The precision specifies the number of significant digits. If the precision is missing, 6 digits are given; if the precision is zero, it is treated as 1. Style e is used if the exponent from its conversion is less than -4 or greater than or equal to the precision. Trailing zeros are removed from the fractional part of the result; a decimal point appears only if it is followed by at least one digit. Should I understand that the zeros in 9.0000000e-05 aren't trailing - because the exponent follows them ? I use -CURRENT cvsup'ed 4-5 days ago. Regards Adi
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