Date: Tue, 08 Dec 2020 05:09:49 +0000 From: bugzilla-noreply@freebsd.org To: bugs@FreeBSD.org Subject: [Bug 251674] std::wcout doesn't print unicode wide characters: std::wcout defaults to "C" locale, not to user's locale Message-ID: <bug-251674-227-RYV06gkUVu@https.bugs.freebsd.org/bugzilla/> In-Reply-To: <bug-251674-227@https.bugs.freebsd.org/bugzilla/> References: <bug-251674-227@https.bugs.freebsd.org/bugzilla/>
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https://bugs.freebsd.org/bugzilla/show_bug.cgi?id=3D251674 Yuri Victorovich <yuri@freebsd.org> changed: What |Removed |Added ---------------------------------------------------------------------------- Summary|std::wcout doesn't print |std::wcout doesn't print |unicode wide characters |unicode wide characters: | |std::wcout defaults to "C" | |locale, not to user's | |locale --- Comment #6 from Yuri Victorovich <yuri@freebsd.org> --- With both clang and gcc this line > std::cout << std::wcout.getloc().name() << std::endl; shows the locale in std::wcout defaults to "C" when it should default to the current user's locale. Without this std::wcout isn't usable from libraries because libraries have = to use the default state of std::wcout and it does not correspond to user's lo= cale without the top-level program setting it in std::wcout. --=20 You are receiving this mail because: You are the assignee for the bug.=
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