Date: Fri, 25 Feb 2000 19:17:08 -0800 From: Alfred Perlstein <bright@wintelcom.net> To: Marco Molteni <molter@csl.sri.com> Cc: freebsd-chat@FreeBSD.ORG Subject: Re: how to do this C preprocessor trick? Message-ID: <20000225191708.S21720@fw.wintelcom.net> In-Reply-To: <20000225182432.A5017@sofia.csl.sri.com>; from molter@csl.sri.com on Fri, Feb 25, 2000 at 06:24:32PM -0800 References: <20000225182432.A5017@sofia.csl.sri.com>
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* Marco Molteni <molter@csl.sri.com> [000225 18:54] wrote:
> Hi all,
>
> I have a function that takes a variable number of arguments:
>
> void d_printf(const char *format, ...)
>
> I would like to make it print automatically the function name
> from which it is called, eg instead of doing
>
> f() { d_printf("f: blabla", x, y, z); }
>
> doing simply
>
> f() { d_printf("blabla", x, y, z); }
>
> To do that, I though of wrapping d_printf() around a macro like
>
> #define dprintf(x) d_printf(__FUNCTION__, x)
>
> but whatever combination I use (also with #), the thing is not going to work:
>
> main.c:231: macro `d_printf' used with too many (4) args
>
> Is it possible to trick the C preprocessor to do what I want?
It's kinda ugly but:
#define panic(A) \
do { \
panic_set_location(__FILE__, __LINE__); \
panic_print_and_die A ; \
} while (0)
you'll need to use your macro like this:
panic(("foo! %s", msg));
there is a way to use varargs macros, but i don't think it's portable.
good luck,
-Alfred
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