Date: Fri, 09 Oct 1998 10:58:48 +0100 From: Brian Somers <brian@Awfulhak.org> To: Bill Fenner <fenner@parc.xerox.com> Cc: Eivind Eklund <eivind@yes.no>, Brian Somers <brian@Awfulhak.org>, Kris Kennaway <kkennawa@physics.adelaide.edu.au>, current@FreeBSD.ORG Subject: Re: Improper sharing of modem bandwidth Message-ID: <199810090958.KAA00774@woof.lan.awfulhak.org> In-Reply-To: Your message of "Thu, 08 Oct 1998 15:21:21 PDT." <98Oct8.152124pdt.177476@crevenia.parc.xerox.com>
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> In message <19981008211441.00286@follo.net> Eivind wrote:
> >#2 is probably the best (from the view of which possibilities it
> >gives), but I also suspect it is what would give most work (unless bpf
> >already can be used this way; then it would just be a question of
> >making PPP use it.)
>
> [Jumping straight in where I know none of the context...]
>
> i = bpf_filter(program, (u_char *)m, ip->ip_len, 0)
>
> is all you need to do to run BPF program "program" on the packet in
> mbuf m.
>
> The BPF program can return the packet's priority (i.e. by looking at
> TCP ports or IP TOS or whatever) and then you could order the packets
> in the queue by their priority.
Maybe this is over-flexible ?
It would be far easier (IMHO anyway) and wouldn't require any bpf
code to create an ioctl something like
struct portlist {
int nports;
u_short port[1];
};
struct portlist *p = (struct portlist *)
malloc(sizeof *p + (nports-1) * sizeof p->port);
p->nports = nports;
for (i = 0; i < nports; i++)
p->port[i] = ...;
ioctl(tunfd, TIOCSETINTERACTIVEPORTS, p);
Closing the device would clear the list, and ppp could simply
#ifdef TIOCSETINTERACTIVEPORTS
to see if it needs to do this...
> Bill
Having said all that, I suspect it would be easier to s/20/100/ as I
originally suggested. If you've got more than 100 packets queued at
a given time, surely the TCP window is way to large.
--
Brian <brian@Awfulhak.org>, <brian@FreeBSD.org>, <brian@OpenBSD.org>
<http://www.Awfulhak.org>;
Don't _EVER_ lose your sense of humour....
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