Date: Thu, 05 May 2005 17:57:58 +0200 (CEST) From: Marco Beishuizen <marco@beishuizen.info> To: "Andrew L. Gould" <algould@datawok.com> Cc: FreeBSD questions mailing list <questions@freebsd.org> Subject: Re: gnumeric portupgrade fails (libgnomedb) Message-ID: <20050505174836.H17820@yokozuna.lan> In-Reply-To: <200505051028.59143.algould@datawok.com> References: <20050505154037.S49572@yokozuna.lan> <200505050916.31297.algould@datawok.com> <20050505171223.X17820@yokozuna.lan> <200505051028.59143.algould@datawok.com>
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On stardate Thu, 5 May 2005, the wise Andrew L. Gould entered:
>>> CONFIGURE_ARGS for the gnumeric port includes "--with-gnome-db".
>>> Perhaps you could try doing make without gnome-db ("make
>>> --without-gnome-db"?) and then do portupgrade.
>>
>> I'll try but if that argument is in the configure, doesn't that
>> imply that Gnumeric needs it?
>
> I think that the fact that it's a configuration argument implies that
> it's optional. (If it wasn't optional, why would the option be
> available.) The question that remains would be whether there are
> features of gnumeric that you use that require gnome-db.
Well I tried to change some options in the makefile but no matter what I
try (--without-gnome-db; --without-gnomedb; --without-libgnomedb) it wants
to compile libgnomedb and it stops with the same error. I also tried a
"make install --without-gnome-db" etc. in the /usr/ports/math/gnumeric
directly, instead of portupgrading it. But that doesn't work either because
it says: make: illegal option -- -. Does this mean that only "--with" is
legal and "--without" is not?
Marco
--
I'm going to live forever, or die trying!
-- Spider Robinson
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