Date: Tue, 4 Oct 2005 13:36:45 -0700 From: John-Mark Gurney <gurney_j@resnet.uoregon.edu> To: Ragnar Lonn <raglon@packetfront.com> Cc: Ceri Davies <ceri@submonkey.net>, Gleb Smirnoff <glebius@FreeBSD.org>, net@FreeBSD.org Subject: Re: ng_tee, right2left, et al Message-ID: <20051004203645.GO716@funkthat.com> In-Reply-To: <4342B4BE.1040304@packetfront.com> References: <20051003130731.GF56760@submonkey.net> <20051003134132.GE73935@cell.sick.ru> <20051003135324.GH56760@submonkey.net> <4342B4BE.1040304@packetfront.com>
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Ragnar Lonn wrote this message on Tue, Oct 04, 2005 at 18:58 +0200:
> Ceri Davies wrote:
>
> >I only call it "wrong" as it didn't agree with Archie's article or my
> >expectations, hence the quotes - I realise that it's subjective.
> >
> >It just seems to me that packets leaving left2right would go to right,
> >as the name implies. I don't really mind either way, it's simply that
> >I found it confusing.
> >
> >
>
> It's not, really. A good idea is to draw the tee node and its hooks on a
> piece of paper.
> Here is an ASCII attempt:
>
>
> left --- right
> \ /
> x
> / \
> r2l l2r
>
> The drawing shows that the left hook is associated with the left2right hook:
> When packets come in on the left hook they are forwarded to the left2right
> hook. Logically, that means they are connected, like in the drawing above,
> and that also means that packets can go in the other direction - i.e. from
> the left2right hook and to the left hook.
I personally imagined the picture like:
l2r
>>>>^>>>>
/ \
left right
\ /
<<<v<<<<
r2l
where the l2r and r2l are taps into the line that goes a certain way... and
so, it'd mean that sending a package on the r2l hook goes to left instead
of right.. not that I use net graph much, but just thought I'd show how
I thought of it...
Though if the behavior matches what the man page states, that's all that
matters, and my drawing is invalidated...
--
John-Mark Gurney Voice: +1 415 225 5579
"All that I will do, has been done, All that I have, has not."
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