Date: Fri, 4 Feb 2000 13:36:30 -0600 From: Dan Nelson <dnelson@emsphone.com> To: Support <rjn103s@mgr3.k12.mo.us> Cc: questions@FreeBSD.ORG Subject: Re: mt erase command question Message-ID: <20000204133630.A18195@dan.emsphone.com> In-Reply-To: <00020406585500.01178@redmobile>; from "Support" on Fri Feb 4 06:46:16 GMT 2000 References: <00020310272102.00687@redmobile> <20000203133300.B17882@dan.emsphone.com> <00020406585500.01178@redmobile>
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In the last episode (Feb 04), Support said:
> Greetins,
>
> On Thu, 03 Feb 2000, Dan Nelson wrote:
> > In the last episode (Feb 03), Support said:
> > > I think that mt erase only erases the first fileSys on the tape. So
> > > my question is if I have 3 fileSys on the tape how do I erase all at
> > > once?
> >
> > The standard "mt erase" is a "long" erase, which should zero out the
> > entire tape.
>
> I was confused because the man page it says a count of 0 disables long erase,
> which in by default. So I assumed that this only cleared the 1st fileSys
>
> So, I was wanting to understand exactly what the command:
> mt erase {count}
> actually does. Please explain the count.
All of the "mt" commands that take a "count" argument, the default is
1, so "mt erase" means "mt erase 1", which is a long erase. "mt erase
0" explicitly asks for a short erase.
> Well, the system starts saying media error and I discovered the block
> size error when the command: mt erase did not fix the problem on the
> tape with multiple fileSys. I took it over to a windoz box and it
> reorted block size errors during an erase from it. I then discovered
> that if I put a count on the mt erase that it as well could correct
> the problem. Hence I am trying to understand the count.
"mt erase" shouldn't report blocksize errors at all. Can you paste in
the exact text?
--
Dan Nelson
dnelson@emsphone.com
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