Date: Thu, 18 Sep 2003 05:59:57 -0500 From: "Charles Howse" <chowse@charter.net> To: "'Rob Lahaye'" <lahaye@snu.ac.kr>, "'Gil Agno Virtucio'" <gihl@nesic.com.ph>, <freebsd-questions@FreeBSD.ORG> Subject: RE: randomize execution the a script? Message-ID: <001801c37dd3$fff4f180$04fea8c0@moe> In-Reply-To: <3F698F28.7080902@snu.ac.kr>
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> > I don't happen to have random installed on my system, however jot is >=20 > It's in /usr/games/random of FreeBSD 4.8. >=20 > > Won't randomNumber=3D$? Just return 0 if the previous command=20 > completes > > successfully? > > Shouldn't it be: > > randomNumber=3D`random -e 60` >=20 > No. In 'man 6 random', it says: >=20 > random [-er] [-f filename] [denominator] >=20 > -e If the -e option is specified, random does not=20 > read or write any- > thing, and simply exits with a random exit value of 0 to > denominator - 1, inclusive. >=20 > So you must capture its exit value for the random number :). Good enough! Thanks for the info! :)
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