Date: Mon, 29 Jul 2013 10:33:53 +0800 From: Julian Elischer <julian@freebsd.org> To: Mateusz Guzik <mjguzik@gmail.com>, Gennady Proskurin <gprspb@mail.ru>, freebsd-current@freebsd.org Subject: Re: ldd runs linux programs Message-ID: <51F5D491.1080803@freebsd.org> In-Reply-To: <20130728204958.GA32322@dft-labs.eu> References: <20130728193110.GB17514@gpr.nnz-home.ru> <20130728204958.GA32322@dft-labs.eu>
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On 7/29/13 4:49 AM, Mateusz Guzik wrote: > On Sun, Jul 28, 2013 at 11:31:10PM +0400, Gennady Proskurin wrote: >> Hello. >> When linux binary is passed to FreeBSD's ldd as argument, this binary is executed. >> I'm sure this is bug :) >> (with security involved) >> > I have a patch for this, but never got around to commit it. > > http://people.freebsd.org/~mjg/patches/ldd-non-freebsd-ignore.diff > > If someone wants, go ahead and steal it. > For those of us that are not ldd experts, why does this happen, what's the history and what happends on Linux? I vagualy remember that linux may somehow execute something in this case but my memory is very vague on the topic.
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