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Date:      Fri, 3 May 2002 02:03:59 +0000
From:      "Richard Shea" <richardshea@fastmail.fm>
To:        "Roger 'Rocky' Vetterberg" <listsub@rambo.simx.org>
Cc:        "FreeBSD Questions" <freebsd-questions@freebsd.org>
Subject:   Re: getting amount of ram with sysctl
Message-ID:  <20020503020359.6C4C56DA62@fastmail.fm>

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On Fri, 03 May 2002 03:17:37 +0200, "Roger 'Rocky' Vetterberg"
<listsub@rambo.simx.org> said:
> Richard Shea wrote:
> 
> > Hi - Sorry I don't have an answer to your question but I would like to
> > do this myself and I don't know how (I don't know how to do it at all,
> > forget about accuracy !). 
> > 
> > I've looked at 'man sysctl' and I can't see the variables you have
> > mentioned - the nearest i've got is 'vm.loadavg'.
> > 
> > Could you post the actual command you're using so that I could try it ?
> > 
> > Sorry about not answering your question, I'm sure someone will !
> > 
> > regards
> > 
> > richard shea.
> 
> The commands are just 'sysctl vm.stats.vm.v_page_size' and 
> 'sysctl vm.stats.vm.v_page_count'.
> 
> Someone just told me about 'sysctl hw.physmem' which gives me a 
> slightly more accurate value, but Im still missing a few megs.
> 
Thanks very much. Just for the record I get

sysctl vm.stats.vm.v_page_size = 4096
sysctl vm.stats.vm.v_page_count = 7345

which comes out as : 30,085,120

and

sysctl hw.physmem = 30,584,832

Which is quite a bit of difference. As far as I'm aware the box I'm
running these on is a '32 Mb machine' which to my way of thinking
should mean that :

sysctl hw.physmem = 33,554,432

I'm sure there's stuff I don't know about this that would account for
some difference between '32 Mb machine' and they physmem but all the
same ~ 9% does seem quite a large discrepancy.

Doubtless someone out there can explain this ... ?

regards

richard shea




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