Date: Fri, 23 Aug 2002 16:33:08 +1000 From: Edwin Groothuis <edwin@mavetju.org> To: "Christopher J. Umina" <uminac@216-164-225-145.c3-0.wth-ubr2.sbo-wth.ma.cable.rcn.com> Cc: freebsd-questions@freebsd.org Subject: Re: expr replacement Message-ID: <20020823063308.GL785@k7.mavetju> In-Reply-To: <20020823021838.V67143-100000@216-164-225-145.c3-0.wth-ubr2.sbo-wth.ma.cable.rcn.com> References: <20020823021838.V67143-100000@216-164-225-145.c3-0.wth-ubr2.sbo-wth.ma.cable.rcn.com>
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On Fri, Aug 23, 2002 at 02:21:14AM -0400, Christopher J. Umina wrote: > I'm writing a simple shell script that finds percentages for me. > The problem here is that when I do the division with expr I always get a > result of 0 since it's below 1. Is there a replacement for this or am I > just doing it wrong? Take a look.. This is my command. > > percentage=`expr $dirttl / $totalsongs` > > where $totalsongs = aroudn 1000 and dirttl = anywhere from 8 to 565. Use a bulldozer: percentage=`perl -e "print $dirttl / $totalsongs"` Edwin -- Edwin Groothuis | Personal website: http://www.MavEtJu.org edwin@mavetju.org | Weblog: http://www.mavetju.org/weblog/weblog.php bash$ :(){ :|:&};: | Interested in MUDs? http://www.FatalDimensions.org/ To Unsubscribe: send mail to majordomo@FreeBSD.org with "unsubscribe freebsd-questions" in the body of the message
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