Date: Sat, 19 Apr 2003 16:53:18 +0200 From: Vincent Jardin <vjardin@wanadoo.fr> To: freebsd-net@freebsd.org, freebsd-atm@freebsd.org Subject: Netgraph ISR conflict with HARP ISR Message-ID: <200304191653.18655.vjardin@wanadoo.fr>
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Hi,
My kernel is compiled with the HARP stack (ie ATM) support. When I load t=
he=20
Netgraph module, the HARP stack is not able anymore to process the incomi=
ng=20
packets.
It is due to the HARP's netisrs entry that is replaced by the Netgraph's =
ISR=20
one !!!. For example, see on the enclosed log, netisrs[AF_ATM] is pointed=
on=20
ngintr.
In fact, it looks like there is a wrong comment within the source code ab=
out=20
AF_NETGRAPH and NETISR_NETGRAPH,
$ grep AF_NETGRAPH */*h =20
net/netisr.h:#define NETISR_NETGRAPH 30 /* same as AF_NET=
GRAPH=20
*/
sys/socket.h:#define AF_NETGRAPH 32 /* Netgraph socke=
ts */
sys/socket.h:#define PF_NETGRAPH AF_NETGRAPH
It means that NETISR_NETGRAPH is not AF_NETGRAPH. In fact it would be=20
impossible because netisrs can contain only 32 entry.=20
netisrs[NETISR_NETGRAPH] would be the 33th one !
whereas
netatm/atm_if.h:#define NETISR_ATM AF_ATM
sys/socket.h:#define AF_ATM 30 /* ATM */
That's ok, but Netgraph has stolen the ATM ISR entry ;-(
What could be the clean solution ?
Vincent
PS:
I get this issue on FreeBSD 4.7:
# gdb -k kernel.debug
(kgdb) add-symbol-file netgraph.ko 0xc11ee000+0x2a64
add symbol table from file "netgraph.ko" at text_addr =3D 0xc11f0a64?
(y or n) y
Reading symbols from netgraph.ko...done.
(kgdb) p ngintr
$5 =3D {void ()} 0xc11f26b8 <ngintr>
(kgdb) p atm_intr
$6 =3D {void ()} 0xc01d35bc <atm_intr>
(kgdb)
netisrs[AF_ATM] 0xc11f26b8 ie ngintr !!
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