Date: Sat, 5 Jun 1999 00:26:00 -0400 (EDT) From: Marc Tardif <intmktg@CAM.ORG> To: freebsd-hackers@freebsd.org Subject: disassembling execve (fwd) Message-ID: <Pine.SOL.4.10.9906050025410.10165-100000@Ocean.CAM.ORG>
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---------- Forwarded message ----------
Date: Fri, 4 Jun 1999 18:39:35 -0400 (EDT)
From: Marc Tardif <intmktg@CAM.ORG>
To: freebsd-questions@freebsd.org
Subject: disassembling execve
How can I disassemble the execve syscall?
I tried compiling the following code:
#include <stdio.h>
void main() {
char *name[2];
name[0] = "/bin/date";
name[1] = NULL;
execve(name[0], name, NULL);
}
... using the following command:
gcc -o program -ggdb -static program.c
... and then debugging with:
gdb program
... followed by:
disassemble main
disassemble execve
The gcc manpage specifies that "on systems that support dynamic linking,
this prevents linking with the shared libraries" regarding the -static
flag. I've noted changes when using 'disassemble main' and using the
-static flag, so it seems FreeBSD is among such systems. Yet, when running
disassemble execve (which is what appears in the main disassembly), I get:
"No function contains the specified address."
Well, I'm stumped, I can't find any way to disassemble execve. Please let
me know if there's a way, the above procedure apparently works on linux
platforms, though execve will appear as __execve in the main disassembly.
Thanks in advance,
Marc
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