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Date:      Mon, 1 Mar 2004 16:38:54 +0200
From:      "Daniel Ben-Zvi" <acid@tapuz.co.il>
To:        "Andy Gilligan" <andy@glbx.net>
Cc:        freebsd-security@freebsd.org
Subject:   Re: procfs + chmod = no go
Message-ID:  <002101c3ff9a$ec47c9c0$0200000a@egzdaniel>
References:  <1298.213.224.103.192.1078085673.squirrel@webmail.boxke.be><xzpvfloiwga.fsf@dwp.des.no> <20040301125053.GA94405@vega.glbx.net>

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It should accomplish the same thing,
but for some reason (and maybe thats how it was intended to be) the whole
process tree can still be viewed from /proc

This may be considered a bug but can be easily fixed with a small kernel
patch.

----- Original Message -----
From: "Andy Gilligan" <andy@glbx.net>
To: <freebsd-security@freebsd.org>
Sent: Monday, March 01, 2004 2:50 PM
Subject: Re: procfs + chmod = no go


> On Mon,  1 Mar 2004 at 12:27, Dag-Erling Smørgrav wrote:
> > "Jimmy Scott" <admin@inet-solutions.be> writes:
> > > Is this possible on FreeBSD 4.9 ? Can't find anything about it in the
> > > manual pages. Just want to prevent lusers from running:
> > >
> > > for file in /proc/*/cmdline; do cat $file; echo; done
> >
> > Why?  They can get the same information from ps(1) or the kern.proc
> > sysctl tree.
> >
> > (in 5.2, you can set security.bsd.see_other_uid to 0 to prevent users
> > from seeing other users' processes)
>
> Surely kern.ps_showallprocs would accomplish the same thing in 4.x ?
>
> -Andy
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