Date: Sat, 18 May 2019 18:10:10 +0200 From: Ralf Mardorf <ralf.mardorf@rocketmail.com> To: freebsd-multimedia@freebsd.org Subject: Re: MIDI timing Message-ID: <20190518181010.7ad84e3d@archlinux> In-Reply-To: <268bfd73bea73e057a0f7deab0ba482cf6ff6ab6.camel@rocketmail.com> References: <20190518124424.aiw4r72zgsedc5sq@hal9000.home.meka.rs> <399c9c55-d751-3689-b590-e9a1dd81a226@ladisch.de> <268bfd73bea73e057a0f7deab0ba482cf6ff6ab6.camel@rocketmail.com>
next in thread | previous in thread | raw e-mail | index | archive | help
On Sat, 18 May 2019 17:56:27 +0200, Ralf Mardorf via freebsd-multimedia
wrote:
>On Sat, 2019-05-18 at 16:30 +0200, Clemens Ladisch wrote:
>> With 120 BPM, you actually have 2304000 ticks per second.
>
>120 BPM = 2 seconds per bar
^^^^^^^ assuming four-four time :D
However, 1/4 note always remains 500 ms.
>(60000ms/120BPM)*4=2000ms
>
>2304000ticks/120BPM=19200
>
>Wouldn't that mean 2304000 ticks per 2 seconds?
Want to link to this message? Use this URL: <https://mail-archive.FreeBSD.org/cgi/mid.cgi?20190518181010.7ad84e3d>