Date: Tue, 20 Sep 2011 19:40:02 -0700 From: Devin Teske <devin.teske@fisglobal.com> To: FreeBSD amd64 <freebsd-amd64@freebsd.org> Cc: Devin Teske <devin.teske@fisglobal.com>, Dave Robison <Dave.Robison@fisglobal.com> Subject: 32-bit route(8) on amd64 host and jails Message-ID: <714EF3C9-33B0-4EF5-B52C-1E95F7F432F9@fisglobal.com>
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I'm noticing that a 32-bit route(8) shows strange behaviour while running u=
nder an amd64 kernel (regardless of whether in the base-host -- utilizing /=
usr/lib32/libc.so.7 -- or in a jail and/or vimage -- 32-bit in nature; resu=
lts are same).
Executable runs fine, but you can't (a) set the default route or (b) view t=
he default route (after successfully setting it with the amd64 build, of co=
urse).
ASIDE: This is under 8.1-RELEASE.
When attempting to set the default route, you get the following...
root@kps0a / # route add -net default 10.10.125.99
route: writing to routing socket: Invalid argument
add net default: gateway 10.10.125.99: Invalid argument
Meanwhile, using the amd64 version, no issues.
When attempting to view the default route, you get the following...
root@kps0a / # route -n get default
route to: default
destination: default
mask: default
gateway: default
flags: <UP,GATEWAY,DONE,STATIC>
recvpipe sendpipe ssthresh rtt,msec mtu weight expire
0 0 0 0 0 0 -1316570637=20
It's the "gateway: default" that's out of place.
--- break ---
Now, where jails and/or vimages come into play is that I can't seem to come=
up with an elegant solution to this.
Copying-in an amd64 build of route(8) is not the "simple" solution it seems=
as it will then expect a new /usr/libexec/ld-elf.so.1(which you can't just=
go replacing because it will break all the 32-bit binaries inside the jail=
).
Maybe, doing the opposite of what the base host does ... (the base has /usr=
/libexec/ld-elf32.so.1). That is, create /usr/libexec/ld-elf64.so.1 to inte=
rpret the drop-in route(8)?
--=20
Devin
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