Date: Mon, 22 May 2000 12:54:31 +0100 From: Ben Smithurst <ben@scientia.demon.co.uk> To: Dan Larsson <dl@tyfon.net> Cc: mj@isy.liu.se, questions@FreeBSD.ORG Subject: Re: calculate sum in sh Message-ID: <20000522125431.L15686@strontium.scientia.demon.co.uk> In-Reply-To: <NEBBJANJCNNAKCPFKHHFAEHDCEAA.dl@tyfon.net> References: <XFMail.000522124146.mj@isy.liu.se> <NEBBJANJCNNAKCPFKHHFAEHDCEAA.dl@tyfon.net>
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Dan Larsson wrote:
> | Not pure shelling, but you can try this with awk
> |
> | File 'crap.txt' is :
> |
> | 1
> | 2
> | 3
> | 20
> |
> | then
> |
> | lagrange> awk '{sum += $0} END{print "Grand total is "sum}' crap.txt
> | Grand total is 26
>
> Perfect! Thanks!
Or, in sh, without cheating, :-)
sum=0
while read n; do
sum=$(($sum + $n))
done < crap.txt
echo "Grand total is $sum"
I'm not sure how portable $(( )) is, but it works at least in Linux
sh and FreeBSD sh, which is all I have access to. If you want more
portability, the awk route is probably better.
--
Ben Smithurst / ben@scientia.demon.co.uk / PGP: 0x99392F7D
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