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Date:      Tue, 18 Sep 2007 01:15:00 +0400 (MSD)
From:      Dmitry Morozovsky <marck@rinet.ru>
To:        Maxim Sobolev <sobomax@FreeBSD.org>
Cc:        current@FreeBSD.org
Subject:   Re: i386 package building on an amd64 system
Message-ID:  <20070918011258.L96165@woozle.rinet.ru>
In-Reply-To: <46EEC481.5010503@FreeBSD.org>
References:  <20070914124630.D14000@woozle.rinet.ru> <46EEC481.5010503@FreeBSD.org>

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On Mon, 17 Sep 2007, Maxim Sobolev wrote:

MS> > possibly stupid question: it there a way to fool jail (real, not
MS> > "tinderbox" one) that it's working under i386 kernel? This would be
MS> > extremely useful for local package building.
MS> > 
MS> > Quick googling does not reveal anything, or did I miss something obvious?
MS> > 
MS> > Thanks in advance.
MS> 
MS> Works here like a charm. The only thing is that you need to set UNAME_p=i386
MS> UNAME_m=i386 and CPUTYPE=i686 variables in the chroot/jail.

I know aboot uname tricks ;-)

What about sysctls revealing amd64 system internals? Did you compare packages 
built by this jailed system with native?

Sincerely,
D.Marck                                     [DM5020, MCK-RIPE, DM3-RIPN]
[ FreeBSD committer:				     marck@FreeBSD.org ]
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*** Dmitry Morozovsky --- D.Marck --- Wild Woozle --- marck@rinet.ru ***
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