Date: Fri, 11 Jun 2021 13:37:10 +0000 From: bugzilla-noreply@freebsd.org To: bugs@FreeBSD.org Subject: [Bug 253893] sed "/^\s*$/d" complains about trailing backslash (\) Message-ID: <bug-253893-227-FDF0wwdKuI@https.bugs.freebsd.org/bugzilla/> In-Reply-To: <bug-253893-227@https.bugs.freebsd.org/bugzilla/> References: <bug-253893-227@https.bugs.freebsd.org/bugzilla/>
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https://bugs.freebsd.org/bugzilla/show_bug.cgi?id=3D253893 --- Comment #12 from Ed Maste <emaste@freebsd.org> --- (In reply to David Schlachter from comment #3) > printf "\n\n\n\n" | sed "/^\s*$/d" Note that this is not actually testing \s since we're matching 0 or more. F= or example, try (on 12.x or earlier): $ printf "\n\n\n\n" | sed "/^x*$/d" This also deletes the blank lines. Or, try: $ printf " \n \n \n \n" | sed "/^\s*$/d" and observe that the except-for-whitespace empty lines are not stripped. --=20 You are receiving this mail because: You are the assignee for the bug.=
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