Date: Sat, 3 Nov 2007 12:49:33 +0000 From: Daniel Bye <freebsd-questions@slightlystrange.org> To: FreeBSD Users Questions <freebsd-questions@freebsd.org> Subject: Re: Determining the number of files in a directory Message-ID: <20071103124932.GB3207@torus.slightlystrange.org> In-Reply-To: <20071103124151.GA3207@torus.slightlystrange.org> References: <538619.51984.qm@web34408.mail.mud.yahoo.com> <20071103124151.GA3207@torus.slightlystrange.org>
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On Sat, Nov 03, 2007 at 12:41:51PM +0000, Daniel Bye wrote:
> On Sat, Nov 03, 2007 at 05:27:06AM -0700, White Hat wrote:
> > This is probably a dumb question; however, I never let a little thing l=
ike=20
> > that bother me in the past.
>=20
> Heheh! You and many more, my friend, myself absolutely included!
>=20
> > Using FreeBSD-6.2 and Bash, how do I determine the number of files in a=
=20
> > given directory? I have tried all sorts of combinations using different=
=20
> > flags with the 'ls' command; however, none of them displays the number =
of=20
> > files in the directory.
>=20
> $ ls | wc -l
>=20
> will show you how many files and directories in the current (target)
> directory. To count just files, and exclude directories, you could try
> something like
>=20
> $ find /target/directory -type f -print | wc -l
Except of course, that would descend into the subdirectories you're trying
not to count... Sorry - an object lesson in not hitting send before you've
tested what you scribbled.
Dan
--=20
Daniel Bye
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