Date: Sun, 22 Oct 2023 16:55:33 +0000 From: bugzilla-noreply@freebsd.org To: bugs@FreeBSD.org Subject: [Bug 274650] sh does not accept -- after -c Message-ID: <bug-274650-227-3xDwZeXH6A@https.bugs.freebsd.org/bugzilla/> In-Reply-To: <bug-274650-227@https.bugs.freebsd.org/bugzilla/>
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https://bugs.freebsd.org/bugzilla/show_bug.cgi?id=274650 Benjamin Takacs <nimaje+fbz@bureaucracy.de> changed: What |Removed |Added ---------------------------------------------------------------------------- CC| |nimaje+fbz@bureaucracy.de --- Comment #1 from Benjamin Takacs <nimaje+fbz@bureaucracy.de> --- FreeBSDs sh doesn't do any option parsing after -c, this makes accidents due to an unusual nammed command impossible and lead to the behaviour you observe. sh tries to run the command ´--´ and uses ´echo $0´ providing ´arg´ as argument. As you don't have any command named ´--´ on your system sh reports it with its name ´echo $0´. That is POSIX incompatiple behaviour. I'm in favour of documenting this incompatibility and closing this report as ´Works As Intended´ -- You are receiving this mail because: You are the assignee for the bug.home | help
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