Date: Mon, 11 Nov 2002 17:19:49 -0500 From: John Von Essen <john@essenz.com> To: Benoit Lacherez <blacherez@ac-bordeaux.fr> Cc: questions@FreeBSD.ORG Subject: Re: awk to remove backet Message-ID: <B17BFFD2-F5C3-11D6-AC50-0003933DDCFA@essenz.com> In-Reply-To: <20021111225743.A7718@milouz.boece.foo>
next in thread | previous in thread | raw e-mail | index | archive | help
Im confused. Wouldn't s/(\([^)]*\))/\1/g just replace exactly what it finds? I think the outer ()'s got mixed up. To take (hello) and change it to hello, you would do: sed 's/\(([\w]+)\)/\1/g' \w is fine if you only want the cases where text only is inside. -John Von Essen On Monday, November 11, 2002, at 04:57 PM, Benoit Lacherez wrote: > What about sed 's/(\([^)]*\))/\1/g' ? To Unsubscribe: send mail to majordomo@FreeBSD.org with "unsubscribe freebsd-questions" in the body of the message
Want to link to this message? Use this URL: <https://mail-archive.FreeBSD.org/cgi/mid.cgi?B17BFFD2-F5C3-11D6-AC50-0003933DDCFA>