Date: Tue, 19 Apr 2005 14:56:12 +0200 From: "Rayene Ben Rayana" <rayene.benrayana@topnet.tn> To: freebsd-net@freebsd.org Subject: Implementing a PPP/L2TP stack using Netgraph Message-ID: 1113913633.77730.mail2.topnet.tn In-Reply-To: <20050419120104.053CA16A4CE@hub.freebsd.org> References: <20050419120104.053CA16A4CE@hub.freebsd.org>
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Hi everybody, I'm trying to connect an IPv6 streaming client to an IPv6 server through a GPRS connection. The client protocol stack should be like this RTP / UDP / IPv6 / PPP(client) / L2TP / UDP / IPv4 / PPP (kernel) / Bluetooth For the moment, I've to implement this one to test. RTP / UDP / IPv6 / PPP(client) / L2TP / UDP / IPv4 / ethernet Ooof I've read some man pages and I think that the netgraph's graph should be like this. ng_socket (/inet6/dgram/UDP) connected to ng_ppp (Inet) ng_ppp (bypass) connected to PPP daemon (???) ng_ppp (link1) connected to ng_l2tp (Session_0001) ng_l2tp (ctrl) connected to ControlEntity (???) ng_l2tp (lower) connected to UDP /IP (but how) IP connected to ng_ether (Upper) Doesn't look to be good :( Please help me. I promise to write a tutorial for the newbies if this works.
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