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Date:      Mon, 15 May 2017 20:18:42 +0000
From:      bugzilla-noreply@freebsd.org
To:        freebsd-bugs@FreeBSD.org
Subject:   [Bug 200553] uniq does not support -c with -u -d
Message-ID:  <bug-200553-8-qfGiPtup58@https.bugs.freebsd.org/bugzilla/>
In-Reply-To: <bug-200553-8@https.bugs.freebsd.org/bugzilla/>
References:  <bug-200553-8@https.bugs.freebsd.org/bugzilla/>

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https://bugs.freebsd.org/bugzilla/show_bug.cgi?id=3D200553

--- Comment #1 from commit-hook@freebsd.org ---
A commit references this bug:

Author: emaste
Date: Mon May 15 20:18:14 UTC 2017
New revision: 318316
URL: https://svnweb.freebsd.org/changeset/base/318316

Log:
  uniq: allow -c to be used with -d or -u

  Bring in some bits from NetBSD and lift the restriction in uniq(1) that
  -c cannot be used with the -d and -u options.  This restriction seems
  unnecessary and is supported at least by GNU, OpenBSD, and NetBSD.  Lift
  the restriction and simplify the show() logic a little bit to maintain
  functionality when -c is provided with -d/-u.

  Also with this change, -d and -u are now actually a mutually exclusive,
  albeit valid, combination.  Given that they both indicate opposite
  behavior, uniq(1) will no longer output anything if both -d and -u are
  supplied.  This is in line with NetBSD as well as GNU.

  Adjust the man page and usage() to reflect that -c is its own standalone
  option.

  PR:           200553
  Submitted by: Kyle Evans <kevans91@ksu.edu>
  Reviewed by:  cem, emaste
  MFC after:    2 weeks
  Differential Revision:        https://reviews.freebsd.org/D10694

Changes:
  head/usr.bin/uniq/uniq.1
  head/usr.bin/uniq/uniq.c

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