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Date:      Mon, 2 Jul 2001 09:38:42 +0100
From:      David Malone <dwmalone@maths.tcd.ie>
To:        cjclark@alum.mit.edu
Cc:        David Hill <djhill@novagate.net>, freebsd-current@FreeBSD.ORG
Subject:   Re: syslogd and -a
Message-ID:  <20010702093842.A13480@walton.maths.tcd.ie>
In-Reply-To: <20010701212044.Q296@blossom.cjclark.org>; from cristjc@earthlink.net on Sun, Jul 01, 2001 at 09:20:44PM -0700
References:  <20010701234125.7a7d3e3a.djhill@novagate.net> <20010701212044.Q296@blossom.cjclark.org>

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On Sun, Jul 01, 2001 at 09:20:44PM -0700, Crist J. Clark wrote:
> Hmmm... Looks like,
> 
>   # syslogd -a 192.168.1.0/29
> 
> Will work and,
> 
>   # syslogd -a 192.168.1.1/29
> 
> Won't.

That's the standard behaviour of a netmask, isn't it? The usual
way to check if host h is in network/netmask n/m is to check if:

	(h & m == n)

this means that the bits of the network which are not in the mask
must be zero.

	David.

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