Date: Tue, 3 Dec 2002 11:42:05 +0100 (MET) From: Paul Everlund <tdv94ped@cs.umu.se> To: Roman Neuhauser <neuhauser@bellavista.cz> Cc: Malik =?iso-8859-2?Q?B=FClent?= <bmalik@ihlas.net.tr>, <questions@freebsd.org> Subject: Re: is there a "replace command" ? Message-ID: <Pine.GSO.4.44.0212031138020.19508-100000@kvist.cs.umu.se> In-Reply-To: <20021203103346.GG56031@freepuppy.bellavista.cz>
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On Tue, 3 Dec 2002, Roman Neuhauser wrote: > # tdv94ped@cs.umu.se / 2002-12-03 11:13:39 +0100: > > On Tue, 3 Dec 2002, Malik Bülent wrote: > > > But my expression has "/" that is there is a "/" in a expression > > > What shall i do ? > > > my expression is "new: 11" I want to change "new: 11" with "new/11" > > > > > > thanks > > > > # echo "new: 11" | sed s/new\:\ 11/new\\/11/ > > you don't have to use slashes for the delimiters. see sed(1). > > roman@freepuppy ~ 1003:0 > echo "new: 11" | sed 's,: ,/,' > new/11 > roman@freepuppy ~ 1004:0 > echo "new: 11" | sed 's:\: :/:' > new/11 > roman@freepuppy ~ 1005:0 > echo "new: 11" | sed 's-: -/-' > new/11 Thanks for the tip! I wasn't aware of that. When it comes to man sed(1): Reading a Kafka book is light weight reading compared to that man page. :-) Best regards, Paul To Unsubscribe: send mail to majordomo@FreeBSD.org with "unsubscribe freebsd-questions" in the body of the message
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