Date: Mon, 21 Oct 2002 11:25:43 +0200 From: Danny Braniss <danny@cs.huji.ac.il> To: freebsd-hackers@FreeBSD.ORG Subject: malloc Message-ID: <E183Yoh-0009TR-00@cse.cs.huji.ac.il>
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the attached program - which shows the 'efficiancy' of our scientific
programmers - tickled my curiosity.
if compiled under Linux, it would run fine on FreeBSD 4.7-stable.
compiled on FreeBSD it would bomb.
so i fixed some kernel values (options MAXDSIZ="(2*1024*1024*1024)")
and it run to complition, but:
fbsd compiled: complex-2 took 23.652872 seconds, mem used=800000000(762M)
linux : complex-2 took 11.969896 seconds, mem used=800000000(762M)
comments?
danny
#include <stdlib.h>
#include <sys/time.h>
#include <stdio.h>
int MAX_N, mem;
int main(int argc , char ** argv){
int i;
int ** arr;
struct timeval t1, t2;
if(argc > 1)
MAX_N = atoi(argv[1]);
else
MAX_N = 100000000;
gettimeofday(&t1, 0);
mem = sizeof (int *) * MAX_N;
arr = malloc(mem);
if(arr == NULL) {
perror("Malloc");
exit(1);
}
for (i = 0 ; i < MAX_N ; ++i ){
arr[i] = malloc(sizeof(int));
if(arr[i] == NULL) {
perror("malloc2");
printf("failed at %d, mem=%d(%d)\n", i, mem, mem/(1024 * 1024));
exit(1);
}
*arr[i] = i;
mem += sizeof(int);
}
gettimeofday(&t2, 0);
printf ("%s took %f seconds, mem used=%d(%dM)\n",
getenv ("HOST"),
t2.tv_sec-t1.tv_sec + (t2.tv_usec-t1.tv_usec)/(float)(1000000),
mem, mem / (1024 * 1024));
for (i = 0 ; i < MAX_N ; ++i ){
if(*arr[i] != i)
printf("GUEVALT! %d] %d\n", i, *arr[i]);
}
exit(0);
}
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