Date: Sun, 14 Jul 2013 00:56:05 +0800 From: "Alex V. Petrov" <alexvpetrov@gmail.com> To: Kevin Oberman <rkoberman@gmail.com> Cc: "freebsd-stable@freebsd.org Stable" <stable@freebsd.org>, Sergey Kandaurov <pluknet@gmail.com> Subject: Re: ls -U don't work? Message-ID: <6087961.Jy4hGFOKS8@alex.super> In-Reply-To: <CAN6yY1uP5h8THBWFO=Tz1bB1JzkjdqcnaLLX9DhAZVLAmj8vqA@mail.gmail.com> References: <8704004.oreYQuEkVL@alex.super> <2813184.tAUhP2F1j4@alex.super> <CAN6yY1uP5h8THBWFO=Tz1bB1JzkjdqcnaLLX9DhAZVLAmj8vqA@mail.gmail.com>
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В письме от 13 июля 2013 09:20:38 пользователь Kevin Oberman написал: On Sat, Jul 13, 2013 at 3:30 AM, Alex V. Petrov <alexvpetrov@gmail.com[1]> wrote: В письме от 13 июля 2013 13:45:30 Вы написали: > 2013/7/13 Alex V. Petrov <_alexvpetrov@gmail.com_>:> > subj:> > ls -Ul>> So, what's the problem? Looking at code,> I'd suggest to try adding -t to actually enable sorting,> otherwise it just prints dates but not sorts.>> > total 0> > -rw-r--r-- 1 alex alex 0 13 июл 15:26 000> > -rw-r--r-- 1 alex alex 0 13 июл 15:25 111> > -rw-r--r-- 1 alex alex 0 13 июл 15:25 222> > -rw-r--r-- 1 alex alex 0 13 июл 15:25 333>> -t enables sorting (by modified date by default),> -U further specifies to sort by birth time. What is the meaning of '-U'?I thought '-U' = '-tr' man ls:"-U Use time when file was created for sorting or printing." -----Alex V. Petrov No, '-U' tells ls(1) to use ctime for all timestamps. By default it uses mtime. So 'ls -U' will print ctime, but to sort by ctime you need 'ls -Ut' or 'ls -Utr'. -- R. Kevin Oberman, Network EngineerE-mail: rkoberman@gmail.com[2] Yes. I knew already.Thank you. -- ----- Alex V. Petrov -------- [1] mailto:alexvpetrov@gmail.com [2] mailto:rkoberman@gmail.com
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