Date: Tue, 9 Oct 2001 14:49:00 +1000 From: "Pietralla, Siegfried P" <siegfried.pietralla@eds.com> To: "'BSD Freak'" <bsd-freak@mbox.com.au>, FreeBSD Questions <freebsd-questions@FreeBSD.ORG> Subject: RE: Outputing a specific line number to standard output Message-ID: <16649A8D5C73D51183B80008C728EEB7CC09E6@AUSYM103>
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hi there,
two simple ways:
using awk:
$ awk 'NR==54{print;exit}' myfile.txt
using head and tail:
$ tail +54 myfile.txt | head -1
regards,
siegfried.
-----Original Message-----
From: BSD Freak [mailto:bsd-freak@mbox.com.au]
Sent: Tuesday, 9 October 2001 14:30
To: FreeBSD Questions
Subject: Outputing a specific line number to standard output
Hi all,
I feel stupid asking this but I have looked in the man page for grep,
sort , cat, head and cut and have not been able to find the answer.
How do I output to standard output a particular line number in a text file?
For example say I want to display line 54 in the file myfile.txt . How
do I do this?
Thanks in advance.....
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