Date: Tue, 11 Dec 2007 17:46:38 -0600 From: Trix Farrar <trix@basement.net> To: Halid Faith <maslak@ihlas.net.tr> Cc: freebsd-questions@freebsd.org Subject: Re: How to replace two strings in a file in the same time with sed command ? Message-ID: <20071211234633.GA3568@basement.net> In-Reply-To: <001001c83c33$669b46b0$dc96eed5@ihlasnetym> References: <001001c83c33$669b46b0$dc96eed5@ihlasnetym>
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On Tue, Dec 11, 2007 at 10:21:22PM +0200, Halid Faith wrote:
> Ok
> But I have another problem,
> I couldn't use any command interior of sed command. That's to say I have=
a
> script;
>=20
> yy=3D"file5"
> for i in `cat file1`;
> do
> sed -e 's/old1/new1\ \'$i'/g' -e 's/old2/'cut -d, -f 1 ${yy}'/g' file2=
>
> file3
> done
>=20
> When I run the script, I get an error, due to using cut command
>=20
yy=3Dfile5
for i in `cat file1` ; do=20
sed -e "s/old1/new1 $i/g" -e "s/old2/`cut -d, -f 1 ${yy}`/g" file2 > fi=
le3
done
I changed the single-quotes to double-quotes so that they can have
their variables interpreted. The problem with this loop is that, at
each iteration, file3 will be overwritten.
--=20
John D. "Trix" Farrar __\\|//__ Basement.NET
trix@basement.net (` o-o ') http://www.basement.net/
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