Date: Thu, 6 Jan 2011 21:10:17 +0000 From: Alexander Best <arundel@freebsd.org> To: Garrett Cooper <gcooper@FreeBSD.org> Cc: svn-src-head@freebsd.org, svn-src-all@freebsd.org, src-committers@freebsd.org, Konstantin Belousov <kib@freebsd.org> Subject: Re: svn commit: r216955 - head/usr.sbin/rtprio Message-ID: <20110106211017.GA46874@freebsd.org> In-Reply-To: <AANLkTimDTq-JXF4gm9KUfo5eJaEXKaRF-CYiycFwdZML@mail.gmail.com> References: <201101041413.p04EDA4f038360@svn.freebsd.org> <20110106204157.GA41314@freebsd.org> <AANLkTimDTq-JXF4gm9KUfo5eJaEXKaRF-CYiycFwdZML@mail.gmail.com>
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On Thu Jan 6 11, Garrett Cooper wrote:
> On Thu, Jan 6, 2011 at 12:41 PM, Alexander Best <arundel@freebsd.org> wrote:
>
> ...
>
> > this causes problems when pid is -0:
> >
> > [id|rt]prio -t -0 and [id|rt]prio 10 -0 will try to run "0" via execvp().
> > beforehand however this will also trigger rtprio().
> >
> > a better solution would be to do:
> >
> > if (argv[2][0] == '-') {
> > proc = parseint(argv[2] + 1, "pid");
> > if (rtprio(RTP_SET, proc, &rtp) != 0)
> > err(1, "RTP_SET");
> > } else {
> > execvp(argv[2], &argv[2]);
> > err(1, "%s", argv[2]);
> > }
>
> How did you get a pid of -0?
pid 0 stands for the current process. see rptio(2).
cheers.
alex
> Thanks,
> -Garrett
--
a13x
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