Date: Thu, 6 Jan 2011 21:14:43 +0000 From: Alexander Best <arundel@freebsd.org> To: Garrett Cooper <gcooper@FreeBSD.org> Cc: svn-src-head@freebsd.org, svn-src-all@freebsd.org, src-committers@freebsd.org, Konstantin Belousov <kib@freebsd.org> Subject: Re: svn commit: r216955 - head/usr.sbin/rtprio Message-ID: <20110106211443.GA48244@freebsd.org> In-Reply-To: <20110106211017.GA46874@freebsd.org> References: <201101041413.p04EDA4f038360@svn.freebsd.org> <20110106204157.GA41314@freebsd.org> <AANLkTimDTq-JXF4gm9KUfo5eJaEXKaRF-CYiycFwdZML@mail.gmail.com> <20110106211017.GA46874@freebsd.org>
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On Thu Jan 6 11, Alexander Best wrote:
> On Thu Jan 6 11, Garrett Cooper wrote:
> > On Thu, Jan 6, 2011 at 12:41 PM, Alexander Best <arundel@freebsd.org> wrote:
> >
> > ...
> >
> > > this causes problems when pid is -0:
> > >
> > > [id|rt]prio -t -0 and [id|rt]prio 10 -0 will try to run "0" via execvp().
> > > beforehand however this will also trigger rtprio().
> > >
> > > a better solution would be to do:
> > >
> > > if (argv[2][0] == '-') {
> > > proc = parseint(argv[2] + 1, "pid");
> > > if (rtprio(RTP_SET, proc, &rtp) != 0)
> > > err(1, "RTP_SET");
> > > } else {
> > > execvp(argv[2], &argv[2]);
> > > err(1, "%s", argv[2]);
> > > }
> >
> > How did you get a pid of -0?
>
> pid 0 stands for the current process. see rptio(2).
rtprio(2) that is. ;)
>
> cheers.
> alex
>
> > Thanks,
> > -Garrett
>
> --
> a13x
--
a13x
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