Date: Sun, 25 Jan 2004 11:27:23 -0500 From: Greg Wooledge <greg@wooledge.org> To: freebsd-questions@freebsd.org, misc@openbsd.org Subject: Re: how to get rid of ^M character using vi Message-ID: <20040125162723.GQ672@griffon> In-Reply-To: <20040125151753.GA1798@gandalf.welch.net> References: <BAY13-F62bUpm0RnzXo00012ad5@hotmail.com> <20040125151753.GA1798@gandalf.welch.net>
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[-- Attachment #1 --] If *every* line ends with ^M (which is almost always going to be the case, if the file has been produced on a DOS/Windows system), then you can just use this: :%s/.$// to delete the last character of each line. This has an obvious downside, but the advantages are that it's easier to type and to read. -- Greg Wooledge | "Truth belongs to everybody." greg@wooledge.org | - The Red Hot Chili Peppers http://wooledge.org/~greg/ | [-- Attachment #2 --] -----BEGIN PGP SIGNATURE----- Version: GnuPG v1.2.4 (GNU/Linux) iD8DBQFAE+5rkAkqAYpL9t8RAnBDAKCSys/NasLgDNhfgIlMm+nBlQSDfwCgjrdo /Ric5PWc4xhRl1vnsIQqrB8= =wAJH -----END PGP SIGNATURE-----help
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