Date: Fri, 30 Nov 2001 14:53:24 -0500 (EST) From: David Miller <dmiller@sparks.net> To: freebsd-hackers@freebsd.org Subject: [OT] alarm() question Message-ID: <Pine.BSF.4.21.0111301452350.27497-100000@search.sparks.net>
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Apologies for this being more C than freebsd, but I did say OT in
the subject...
In the most basic use of an alarm, like this:
#include <stdio.h>
#include <unistd.h>
#include <signal.h>
sig_t
signal(int sig, sig_t func);
static void bzzt() {
printf("In routine bzzt now, timer expired after 3 seconds\n");
}
main() {
signal(SIGALRM, bzzt);
alarm(3);
system("/usr/bin/host -t soa 111.0.12.in-addr.arpa");
printf("Done\n");
}
Why does the alarm go off but not interrupt the system call? bzzt() is
executed, but the program doesn't print Done and exit for a minute plus.
Pointers to FM to RT welcome.
Thanks,
--- David
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