Date: Fri, 14 Sep 2007 13:51:05 +0400 (MSD) From: Dmitry Morozovsky <marck@rinet.ru> To: Kenneth Vestergaard Schmidt <kvs@binarysolutions.dk> Cc: current@FreeBSD.org Subject: Re: i386 package building on an amd64 system Message-ID: <20070914134928.Y14000@woozle.rinet.ru> In-Reply-To: <m11wd1oabk.fsf@coruscant.pil.dk> References: <20070914124630.D14000@woozle.rinet.ru> <m11wd1oabk.fsf@coruscant.pil.dk>
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On Fri, 14 Sep 2007, Kenneth Vestergaard Schmidt wrote: KVS> > possibly stupid question: it there a way to fool jail (real, not "tinderbox" KVS> > one) that it's working under i386 kernel? This would be extremely useful for KVS> > local package building. KVS> KVS> We do it by creating an i386 chroot on the amd64-machine. Works perfectly. I'm a bit frightened by information which is exported by kernel (which is 64bit) - or is this case treated specially? We can fool uname, but what about sysctls? Sincerely, D.Marck [DM5020, MCK-RIPE, DM3-RIPN] [ FreeBSD committer: marck@FreeBSD.org ] ------------------------------------------------------------------------ *** Dmitry Morozovsky --- D.Marck --- Wild Woozle --- marck@rinet.ru *** ------------------------------------------------------------------------
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