Date: Sun, 02 Nov 2008 05:50:41 -0600 From: Josh Paetzel <jpaetzel@FreeBSD.org> To: David Allen <the.real.david.allen@gmail.com> Cc: "freebsd-questions@freebsd.org" <freebsd-questions@freebsd.org>, Sahil Tandon <sahil@tandon.net> Subject: Re: OT: Shell Script using Awk Message-ID: <490D9411.9070002@FreeBSD.org> In-Reply-To: <2daa8b4e0811012210k40e92816ydbc96e36abe9ee5@mail.gmail.com> References: <2daa8b4e0811011821q210ae3a5j8f612a0fc79e8844@mail.gmail.com> <20081102045414.GA13745@shepherd> <2daa8b4e0811012210k40e92816ydbc96e36abe9ee5@mail.gmail.com>
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David Allen wrote:
> On 11/1/08, Sahil Tandon <sahil@tandon.net> wrote:
>> David Allen <the.real.david.allen@gmail.com> wrote:
>>
>>> My apologies for asking on this list, but I'm stuck without Perl and need
>>> to use awk to generate a report.
>>>
>>> I'm working with a large data set spread across multiple files, but to
>>> keep things simple, say I have A Very Long String that containing records,
>>> each delimited by a single space. I need to print those records in
>>> columnar format, but with only 7 columns per line:
>>>
>>> record1 record2 record3 record4 record5 record6 record7
>>> record08 record09 record10 record11 record12 record13 record14
>>> ...
>> A small sh script:
>>
>> #!/bin/sh
>> awk ' {
>> for (i=1; i<=NF; i++) {
>> printf("%s ", $i)
>> if (i % 7 == 0) { printf("\n") }
>> }
>> if (NF % 7 != 0) { printf("\n") }
>> } ' input
>
> An elegant solution if ever I read one. The mod operator should have
> been the first thing that came to mind.
>
> I'm not sure whether I need a class in remedial math, or remedial awk,
> but either way, my thanks for the solution.
Just in case you've never discovered column, piping the output of this
to column -t will get you nice formatting for free.
- --
Thanks,
Josh Paetzel
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