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Date:      Sat, 9 Nov 1996 18:22:36 +1100
From:      Bruce Evans <bde@zeta.org.au>
To:        amir@comtrol.com, erich@lodgenet.com
Cc:        hackers@freebsd.org
Subject:   Re: timeout() function
Message-ID:  <199611090722.SAA00055@godzilla.zeta.org.au>

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>ticks are 1/100 sec, so with a timeout of 1, your function will be

Ticks are 1/hz second.  hz just happens to be 100 in standard
configurations.  Drivers should not assume this.

See timeout(9).

Bruce



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