Date: Sun, 26 Jan 2014 22:32:55 +0100 From: rank1seeker@gmail.com To: "Tim Kientzle" <tim@kientzle.com> Cc: hackers@freebsd.org, Mark Blackman <mark@exonetric.com> Subject: Re: Is this a regex bug? Message-ID: <20140126.213255.017.3@DOMY-PC> In-Reply-To: <88CC5471-AD3A-4841-89BB-23D585F77079@kientzle.com> References: <20140126.210430.622.1@DOMY-PC> <88CC5471-AD3A-4841-89BB-23D585F77079@kientzle.com>
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> -n is being interpreted as an option to ‘echo’ and being swallowed before it gets to egrep. > > - Mark I've tried without echo printf "\-n\n" | egrep '^\-[[:alnum:]]+$' This works! Thanks for pointing out. > Try without the grep: > > $ echo '-m' > -m > $ echo '-n' > $ echo '-o' > -o > $ man echo > > > > > On Jan 26, 2014, at 1:04 PM, rank1seeker@gmail.com wrote: > > > Or am I crazy? > > > > echo '-m' | egrep '^\-[[:alnum:]]+$' > > echo '-n' | egrep '^\-[[:alnum:]]+$' > > echo '-o' | egrep '^\-[[:alnum:]]+$' > > > > Guess what? > > Only middle one, '-n' doesn't match it. > > Is this an RE bug or I clearly ain't seeing obvious?! > > > > echo '-n' | egrep '^\-[0-9A-Za-z]+$' > > Doesn't work either > > > > 9.2-RELEASE-p3 i386
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