Date: Tue, 12 Oct 2004 11:42:32 -0500 (EST) From: Sam <sah@softcardsystems.com> To: =?iso-8859-1?q?Dag-Erling_Sm=F8rgrav?= <des@des.no> Cc: freebsd-arch@freebsd.org Subject: Re: mbuf w/o pkthdr? Message-ID: <Pine.LNX.4.60.0410121136540.30953@athena> In-Reply-To: <xzpy8ict0cy.fsf@dwp.des.no> References: <Pine.LNX.4.60.0410121115430.30953@athena> <xzpy8ict0cy.fsf@dwp.des.no>
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>> Are all packets supposed to have the M_PKTHDR flag? Why? > > IIRC, M_PKTHDR indicates the first mbuf in a chain when a packet is > split across multiple mbufs. This usually only happens for outgoing > packets, where protocol headers are constructed in separate mbufs > which are prepended to the chain as the packet moves down the stack. That's kind of my understanding (with some PACKET_TAG* stuff going on). I don't have split headers, though. Neither would an arp frame, but he too gets a packet header and fills it out. I don't mind following suit, I'm just wondering what the convention is for. Perhaps we use mbufs without packet headers for something special? Samhome | help
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