Date: Thu, 22 Dec 2005 20:46:21 +0100 From: Tijl Coosemans <tijl@ulyssis.org> To: freebsd-questions@freebsd.org Cc: Mikhail Teterin <mi+mx@aldan.algebra.com> Subject: Re: what's an equivalent for the following Perl one-liner? Message-ID: <200512222046.22133.tijl@ulyssis.org> In-Reply-To: <200512221414.10321.mi%2Bmx@aldan.algebra.com> References: <200512211704.49530.mi%2Bmx@aldan.algebra.com> <20051222183250.GB39217@dan.emsphone.com> <200512221414.10321.mi%2Bmx@aldan.algebra.com>
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On Thursday 22 December 2005 20:14, Mikhail Teterin wrote: > четвер 22 грудень 2005 13:32, Dan Nelson Ви написали: > > In the last episode (Dec 21), Mikhail Teterin said: > > > I'd like a sed string, that will remove both the carriage returns > > > and the blanks at eol in one go. Perl appears to recognize the \r > > > character and DTRT: > > > > > > perl -p -e 's,[ \r]+$,,' < in > out > > > > > > What's the sed's equivalent? Thanks! > > > > sed -E 's,[ ^M]*$,,' < in > out > > > > Note the ^M is a single control-character (entered via Ctrl-V > > Ctrl-M at a shell prompt for example). > > Yes, I used this in the past, but the ports' Makefiles are supposed > to be ASCII-only :-( Try col(1) or tr(1) to remove the carriage return and then sed to remove the spaces.help
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