Date: Mon, 11 Aug 2003 18:17:25 -0400 From: Michael Conlen <meconlen@obfuscated.net> To: Constantine <cnst@rbcmail.ru> Cc: freebsd-questions@freebsd.org Subject: Re: simple sh scripting. How to put a result of a command to a variable? Message-ID: <3F3815F5.5070302@obfuscated.net> In-Reply-To: <3F380F5D.6020904@rbcmail.ru> References: <3F380F5D.6020904@rbcmail.ru>
next in thread | previous in thread | raw e-mail | index | archive | help
Constantine wrote:
> Hello!
>
> I am writing a script, which involves unzipping some files. I would
> have to unzip 4 different zip-files from some directory, and I would
> need to unzip them to the directory, which would have the same name in
> it as the original zip-file, i.e. I would like to run something like
> "ls *.zip", have each file name recorded in some variable, and do a
> loop like "unzip $filename[$i] -d $filename[$i].unzipped/". Can
> someone help me with the code? How can I put the results of a command
> to a variable?
If I understand you properly I think the following would do what you want
#!/bin/sh
for i in `ls *.zip`
do
unzip ${i} -d ${i}.unzipped
done
Want to link to this message? Use this URL: <https://mail-archive.FreeBSD.org/cgi/mid.cgi?3F3815F5.5070302>